IAL Oct 2019 U4

1)A 2)D 3)A 4)A 5)C 6)D 7)A 8)D 9)C 10)D
11)a)/\mv=1/2bh=1/20.1660=mu-mv=(5610^-345)-(5610^-3v), v=-40.7ms^-1
11)b)Calculate the displacement moved after each frame and then divide it by the time of the video just before it hit the racket
12)a)Straight equidistant lines from conducting material plate near the positive terminal of the batter to the other conducting material plate.
12)b)1/2CV^{2=E=1/21210-12*52=} 6J
12)c)C[eq]=1210^-12+1.510^{-12=13.5*10-12F,} V=V[o]e^{-1=5*e-1=1.84V}
13)a)W downwards T angled left upwards
13)b)w=2pif=2pi62/60=6.49, T=2pi/6.49=0.968, a=rw^2=v2/r, v=/w=6.49=2.54ms^-1, /\t=r/v2theta, theta=/\tv/2r=0.9682.54/227010^-3=4.55 degrees
14)a)Positive ions are released from the ion source. These positive ions are accelerated towards dee 1, which is initially given a negative potential to attract the positive ions. Once inside dee 1 the positive ions move at constant speed. A uniform magnetic field is applied perpendicularly to the dees by the electromagnet. This magnetic field makes the positive ions move in a circular path. The positive ions turn around and move towards the gap from dee 1 into dee 2. The alternating voltage reverses giving dee 2 a negative potential. When the positive ions cross the gap from dee 1 into dee 2 they are accelerated towards dee 2 by the negative potential.
14)b)i)18^{[8]O-->18[9]F+0[-1]beta,} therefore it is a beta particle which is a fast moving electron
14)b)ii)F=kQ[1]Q[2]/r^{2=8.991091.610-19161.610-19/(3.2*10-15)2=360N}
15)a)As the pion travels in the opposite direction to the proton therefore it has a negative charge
15)b)0
15)c)i)Into the page
15)c)ii)Measure the length from start of the path to the end for both to calculate the distance and as distance is directly proportional to speed use this as ratio then multiply it by the mass calculated before and find the momentum of the pion
15)c)iii)One particle line going and other 2 in opposite direction and proton side smaller than the pion side
16)a)The constant magnetic field applied perpendicular to the dees exerts a force on the ions that makes them move in a circular path. The speed inside a dee remains constant. The speed of the ions increases as they move from one dee to the next. This is because they are attracted to the oppositely charge dee. The ions spend an equal amount of time in each dee, as they speed up, the circular path increases in radius and they travel further in each dee.
16)b)i)As its B=fiA and which fi * t therefore it shows B the magnetic field
16)b)ii)Nfi=BAN, B=Nfi/AN=5002.5/2.510^-3500=1000T
16)c)A graph with same phase and time period but with lower amplitude
16)d)As there is more charging flowing across so it balances out and the force between q1 and q2 particles increases
17)a)5.910³931.5=5.5010^6kg/1.6710^{-27kg=3.29*1033} times
17)b)High energy is needed for high energy collisions to create high mass particles
17)c)0.4710^-3/1.4210^{-12s=3.30*108ms-1} as it is more than the speed of light it is relativistic that means the mass will increase
17)d)As it allows more progress and more data sharing so it can peer reviewed and tested
17)e)We learn about new particles which can be used in human devices or services to benefit us